x^+4x=-8-2x

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Solution for x^+4x=-8-2x equation: 



x^+4x=-8-2x

We move all terms to the left:

x^+4x-(-8-2x)=0

We add all the numbers together, and all the variables

x^+4x-(-2x-8)=0

We add all the numbers together, and all the variables

5x-(-2x-8)=0

We get rid of parentheses

5x+2x+8=0

We add all the numbers together, and all the variables

7x+8=0

We move all terms containing x to the left, all other terms to the right

7x=-8

x=-8/7

x=-1+1/7

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